So the probability that the performance serial number of player A is 1 is 17...(3 points).
(ii) Let b represent "at least one of the performance serial numbers of two players, A and B, is odd",
B means "The serial numbers of the performances of A and B are even".
So p (b) = 1? p(。 B)= 1？ A23A27=67。
Therefore, the probability that at least one of the performance serial numbers of two players A and B is odd is 67...(6 points).
(iii) The possible values of x are 0, 1, 2, 3, 4, 5, …(7 points).
So p (x = 0) = 12A27 = 27,
p(X = 1)= 10a 27 = 52 1，
P(X=2)=8A27=42 1，
P(X=3)=6A27= 17，
P(X=4)=4A27=22 1，
P (x = 5) = 2a27 = 12 1...( 10)
So the distribution list of x is
X 01234 5p27 521421has been praised. What's your comment on this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and provide free professional consultation for other similar problems through Baidu Law Professional Edition. On May 24th, 2022, Party A, Party B, Party D and Party E each selected three people to participate in the speech contest, and the probability that Party A was elected was 2020- 10- 15. A, B, C, D, E, f A: The champion is either A or B; B: The champion is C or D32022-09-29. A, B, C, D, E and F who participated in the finals, three people guessed before the game. A: The champion is either A or B; B: The champion is C or D2020-09-05. Three out of seven people were selected to take part in the speech contest. If one of them happens to participate, how many kinds are there? 2020-09-02: Four out of seven people take part in the speech contest, and at most two are A, B and C. How many ways are there? 20 14-02-20 A city held a singing contest and invited four abcd instructors. Each contestant can choose a 72016-12-01by drawing lots. There was a lucky draw in a speech contest held in a class. The rules of the activity are: two students who entered the finals. Everyone has only one chance to draw a lottery. 220 16-09- 17 A school held a speech contest in the third grade. * * * A total of 10 students participated in this contest, including 3 students from Class One, 2 students from Class Two and 5 students from other classes. What if the second party in the lottery is adopted? & gt recommended for you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256e9edab64034f1a07? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? The price of electric cars has dropped many times. Is the quality guaranteed? What impact will the "network toilet" have? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720062705；