Solution: Considering the arrangement of unit A and unit B,
Units A and B can be arranged in any two of the six positions, and there are 30 possible results.
(1) Let A mean "The performance serial numbers of A and B are even",
Then a contains six results,
So the probability is P(A)= =.
(2) Let b represent "the performance serial numbers of unit A and unit B are not adjacent",
The serial numbers indicating A and B are adjacent and contain 10 results.
So P(B)= 1-P( )= 1- =.