When there are only 3, 4 or 5 people, 3 must put forward "3-99; 4-0; 5- 1 "and passed smoothly. Give five gems, and five will be enough, which is better than letting three die and four make plans. So 5 is for 3, and 4 is against it. Only the cost of a gem can win the support of 5.
When there are only two people, three people, four people and five people, two people must put forward "2-99; 3-0; 4- 1; 5-0 "and passed smoothly. 3 must oppose any scheme of 2, and you only need a gem to buy the support of 4, so you don't have to consider 5 at this time.
So, the correct answer is:
When there are five people, 1, 2, 3, 4, 5, 1 must put forward "1-98; 2-0; 3- 1; 4-0; 5- 1 "and passed smoothly. First of all, we can know that 2 definitely opposes the scheme of 1; 1 If you want to win support, you only need to win over the unfavorable party in the scheme of 2. Therefore, it is the most economical scheme to give 3 and 5 a gem each.