Four archers with a known number of participants of 1 ~ 4 took part in the archery competition. (1) They were placed in the target position of 1 ~ 4 by drawing lots, and there was just one attempt.

The event involved in the experiment is to arrange four athletes in four positions.

Choose one of the four athletes with the same target number and entry number, and there is C4 1 method.

There are two ways for the other three athletes to have different target numbers and entry numbers.

∴ The probability that only one athlete draws the same target number as the entry number is P = C 14? 2A44=824= 13

(2) (1) As can be seen from the table, the probability that two people each shoot once and miss the eighth ring is

p =( 1-0.2)( 1-0.32)= 0.544

∴ The probability that at least one person hits the 8th Ring is p= 1-0.544=0.456.

②∫eξ 1 = 4×0.06+5×0.04+6×0.06+7×0.3+8×0.2+9×0.3+ 10×0.04 = 7.6

eξ2 = 4×0.04+5×0.05+6×0.05+7×0.2+8×0.32+9×0.32+ 10×0.02 = 7.75

Therefore, Archer II has a high level of archery.