Help me solve the problem of numerical reasoning

1 7 () 3 1 49 7 1

7-1= 6,49-31= 18,71-49 = 22,18 and 22 differ by 4. Can we assume that the new series is 6? -7,3 1-? ,18,22, they are actually a arithmetic progression whose last term differs from the previous term by 4, so we come to the conclusion? -7=6+4,? = 17, and then check whether the next item is correct, 6, 10, 14,18,22, which is exactly what we are talking about in arithmetic progression, so our answer is 17.

-3 -2 5 () 6 1 122

The cube of 0 -3 is equal to -3.

The cube of 1 -3 is equal to -2.

2 to the third power -3 equals 5.

That is, 3 to the third power -3 equals 24.

The third power of 4 -3 is equal to 6 1.

The cubic of 5 -3 is equal to 122.

2 2 4 12 48 ()

The latter item is divided by the former item to get 1, 2, 3, 4, and then what? /48=5,? That is, 48×5=240

0 9 26 65 124 ()

The cubic of 1-1 is equal to 0.

The third power of 2+1 equals 9.

The third power of 3-1 equals 26.

The third power of 4+1 equals 65.

The cubic of 5-1 is equal to 124.

The next term is the cubic of 6+1, which is equal to 2 17.