The problem solving process is as follows:
Option 1: Set X pigeon coops.
6x+3+5=8x .
x=4 .
6x+3=27。
A ***4 pigeon coops, 27 pigeons.
Solution 2: With X pigeon cages and Y pigeons, then
( 1)6*x+3=y .
(2)8*x-5=y .
From (2)-( 1):
2*x-8=0
(3)x=4 .
Substitute (3) into (1).
y=27 .
A: There are 27 pigeons and 4 pigeon cages.
Option 3: Set X pigeon coops.
6x+3+5=8x
6x+8=8x
8x-6x=8
2x=4
x=4
6x+3=27
A: One ***4 pigeon coops and 27 pigeons.
Extended data:
An equation must be an equation, but an equation is not necessarily an equation.
Example: a+b= 13 conforms to the equation, and there are unknowns. This is an equation and an equation.
1+ 1=2 , 100× 100= 10000。 These two formulas are consistent with the equation, but there are no unknowns, so they are not equations.
In the definition, the equation must be an equation, but there can be other equations, such as 1+ 1 = 2,100×10000 =10000, all of which are equations. Obviously, the range of the equation is larger.
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