If three black, white and gray balls are not put back, what is the probability of getting the black ball for the second time?

Classical probability: P(A)=m/n

Denominator: n = a (3,2) method

Molecules: Two kinds of white or gray were obtained for the first time, and 1 black ball was obtained for the second time.

m=2* 1=2

∴P(A)=2/6= 1/3