∫g = mg, ∴ mass of Helan stone: m = gg =1.4n10n/kg = 0.14kg =140g.
(2) According to the measuring cylinder shown in the figure, measure the volume of water, that is, the volume of Helan stone V=50ml=50cm3,
The density of Helan stone ρ = mv =140g50cm3 = 2.8g/cm3 = 2.8×103kg/m3.
(3) hanging Helan stone under a spring dynamometer and measuring its gravity G,
When Helan stone sinks into the water, read the pointer f of the spring scale, and the buoyancy of Helan stone is F = G-F,
∫F float =ρwater gV row,
∴ The volume of Helan stone V=V row =F floating ρ water g=G? Fρ water g
So the answer is: (1)140; (2)50; 2.8× 103; (3) The specific method of measuring the volume of this Helan stone is as mentioned above.