You asked more than half of your kind. Deductive method.
When there are 1 robbers, how to divide them is your own. 100
When there are two robbers, it will always be 50%, but not more than half, so the fourth robber can only earn 0. 100 to survive. Even so, he may not survive. If another robber dies, you will still get 100. If you kill as many people as possible, when there are two robbers, the fourth robber will die. So, in order to survive, he will agree with robber number three, just to survive. Will definitely die or be killed.
When there are three robbers, no matter how they are divided, the fourth robber will agree to live, so the third robber really wants the second robber to die. So as long as it can kill robber No.2, the gems are all their own. He won't agree with anything number two says. Similarly, at this time, robber No.5 objected, because he didn't have a gem, and it was 2V 1. Overruled. Robber number five still has no jewels. 100 0 0
When there are four robbers, the second robber puts forward the distribution suggestion. Of course, he doesn't want to die. Similarly, the only thing he can do to survive is to give the No.4 robber 1 jewelry, because as long as he dies, No.4 robber will get nothing. Similarly, robber number five became the key. If robber No.5 opposes himself, he will become 2V2, so he will still die. So 1 gem must also be given to robber No.5, which is 3V 1 when voting. So robber number two wants robber 1 to die, so he can get 98 gems. 98 0 1 1
When there are five robbers, 1 robbers put forward distribution opinions. In order to survive, the robber 1 must win two votes to get a 3V2 pass. First of all, robber 2 really wants 1 to die. So number two will definitely object. Robber No.3 knows that if 1 dies, he can't get 1 gem (see the situation of four robbers sharing gems), so he just needs 1 to give himself a gem. As long as 1 dies, robber No.4 will definitely get 1 gem (see the situation that four robbers share gems), so as long as there are not more than two gems, the life and death of 1 has nothing to do with himself. The fifth is the same as the fourth. At least 1 gem was obtained when 1 died. Because you want to kill as many people as possible, you should give yourself at least 2 yuan. Because robbers are greedy. I think the most. 1 will win No.3 first (you can buy it as long as you give it to 1, unlike No.4 and No.5, which need 2), and then five people will share the time like this: 97 0 1 2 0 or 97 0 1 0 2.
If you pass halfway, the answer will be different.
Let's take a look at the other half.
When there are 1 robbers, how to divide them is your own. 100
When two robbers, no matter how they are divided, belong to the fourth robber. The vote must be 1V 1. Robber 100 0 5 has nothing.
When the three robbers passed, half of them passed, so he wanted to win No.5, so 99 0 1 voted 2V 1 passed.
When there are four robbers, No.3 wants No.2 to die, so No.3 objects. Robber number two wants to win 1 ticket. He pursued robber number four. Because if he dies, robber No.4 will get nothing (see three robbers sharing gems), so 990 10 So robber No.4 will allow himself to cross 2V2.
When there are five robbers, No.2 Hope 1 votes against it, and No.2 Kloc-0/needs to win over two people to support itself. You need 1 gem to win No.3 (four people divide No.3 without gems), two gems to win No.4 (if four people divide, he will get 1 gem) and 1 gem to win No.5 (if four people divide, he has no gems), so he will win No.3 and No.5 980/kloc-