(1)∵ Three Asian national teams are divided into groups A, B and C, with 33 points for each team.
The remaining six teams were divided equally among Group A, Group B and Group C, with C62*C42*C22 points.
Therefore, each of the three groups has an Asian national team with a score of P33*C62*C42*C22.
∴ ask probability P=
P33*C62C42C22/C93*C63*C33
=9/28
(2) The event "at least two Asian national teams are in the same group" is the opposite of the event "three groups each have an Asian national team".
The probability of ∴ is 1-9/28 = 19/28.