At least three. If it is difficult to prove, it will be the other way around. Then find the probability that there is only one a.
52 * * There are 52C5 ways to draw five.
There are only 1 A in 52 A's, so one of the four A's is 4C 1.
Take four of the remaining 48 ... 48C4.
So the answer is 1-(4C 1 times 48C4)/(52C5).