Don't put this question back. Remove a 7, leaving 5 1 card, of which 7 has 3 cards left.
When calculating lottery tickets, the premise is that the previous lottery results are unknown and the next probability is the same.
For example, * * * has 8 lots, of which only 1 is signed, the probability of the first person drawing is 1/8, and the probability of the second person drawing is
(1-1/8) * (1/7) =1/8, so the probability is the same.
However, if you know that the first person didn't win, the second person's smoking is equivalent to starting over. If 1 is drawn from 7 hands, the probability will change.
If you put the lottery back, and then use my example above to replace it with the lottery back, the probability of the second person winning the prize is (1-1/8) * (1/8) = 7/64.