Discussion on the possibility of China Jinhua winning the Australian Open women's singles championship from the perspective of probability theory?

1. Li Nasheng Serena Zheng Jiesheng Haining 0.2*0.3

2. Li Nasheng Serena Zheng Jie negative Haining Li Nasheng Haining 0.2*0.7*0.3.

3. Li Na loses Serena and Zheng Jiesheng Haining and Zheng Jiesheng Serena is 0.8*0.3*0.2.

Add them together.

0.2*0.3+0.2*0.7*0.3+0.8*0.3*0.2=0。 15