Set four labels: A, B, C and D (take 10, 20, 30 and put 10 respectively).
Since you want all four labels, you can't be short of one. Let ABC have 1 apple each. In order to keep the number of apples in the basket unchanged, D should have 6 apples, (6* 10= 10+20+30). So there is 3* 1+6=9, plus B 1, D2, (20=2* 10), and the number of signatures is *** 12. In the future, increase 1 every1a.
Now, we add four A's and four D's to the above 12 to make 20, namely A5, B2, C 1 and d 12. (The number of apples remains unchanged: 5 * 10+2 * 20+ 1 * 30 =
This is just one of the schemes, and there are many others.