During the military training, students in a school fired live ammunition. (1) Six students from 1 ~ 6 were drawn to the target position of 1 ~ 6, and there were exactly three students.

(1) Let an event with the same target number as that selected by three students be A, then the number of basic events contained in event A is 2c 6 3, and the number of six students who draw lots to reach the target number 1 ~ 6 is A66.

P (a) = C36a66 = 1 18, because the possibility of each student drawing a certain target is equal.

Answer: The probability that three students draw the same target number is 1 18.

(Ⅱ) Assuming that the events that the classmate just hit the 28th ring, 29th ring and 30th ring are B, C and D respectively, and the event that he can win the title of shooting pacesetter is E, then the events B, C and D are mutually exclusive.

∫P(B)= 3×(0. 1)2×0.2+3×0. 1×(0.2)2 = 0.0 18，

P(C)=3×(0. 1) 2 ×0.2=0.006，

P(D)=(0. 1) 3 =0.00 1，

∴p(e)=p(b+c+d)=p(b)+p(c)+p(d)=0.0 18+0.006+0.00 1=0.025.

Answer: The probability that this student can get the title of shooting pacesetter is 0.025.