Ii) Suppose there are only three people left in the end, and only three need to give five a gold coin, thus avoiding the situation of I), so three and five will agree, so the allocation scheme is 99,0, 1.
Iii) Suppose there are four people left, 2, 3, 4, 5. As long as you give 4 a gold coin, you will avoid the situation of ii), so both 2 and 4 will agree, so the allocation scheme is 99,0, 1 0.
Iv) In the presence of five people, if 1 gives nothing, everyone will definitely object, because the situation behind the objection will not be worse than nothing, so it takes two people to get three people to agree, so the plan should be 98,0, 1, 0 1.
2.I) Suppose there are only four or five people left, but four people object and five people can get 100 gold coins, so the distribution is 0, 100.
Ii) Suppose there are only three people left in the end, and 3 only needs to give 4 a gold coin, thus avoiding the situation of I), so 3 and 4 will agree, so the allocation scheme is 99 1 0.
Iii) Suppose there are four people left, 2, 3, 4, 5. If three people agree, then the other two people must get better benefits than veto, that is, 4 and 5 to ii), so the distribution scheme is 97, 0, 2, 1.
Iv) In the presence of five people, to get the consent of three people to 1, it is necessary to make 3 and 5 better than those in iii), so the allocation scheme is 97,0, 1, 0,2.
3. 100 pirate points 100 gold coins, 1 pirates need the support of 49 other pirates. If nothing is given, everyone will definitely object, because the latter situation will not be worse than nothing, so similar to the above analysis, the allocation scheme is 5 1 65438+.
4.I) Assuming that there are 5 left in the end, he can get 104 gold coins;
II) Suppose there are 4,5 left in the end, and at this time there are 65,438+003 gold coins left, and all four can be kept for themselves, and the distribution is 65,438+003,0.
Iii) Assuming that there are 3,4,5 left, there are 65,438+002 gold coins left at this time, and the distribution is 65,438+0010,65,438+0, which can be supported by 5.
IV) Assuming that there are 2, 3, 4 and 5 left, there is still 10 1 gold coin, and the distribution is 100, 0, 1 0, which can be supported by 4.
V) When five people are present, you only need to give 1 to 3 and 5, and you don't need to take out one of your own, so the result is still 98,0, 1, 0, 1.