It is known that a scientific research team has four male members and two female members, one of whom can't speak English and the others can. Now, draw lots.

The number of two of the six species is c (2 6) = 6! /(2! 4! ) =28.

(1) The number of male species is c (2 4) = 4! /(2! 2! ) =6 species, and the number of female species is c (2 2) =1species.

The probability that the members of the research group are of the same sex P=(6+ 1)/28= 1/4.

(2) There are only 1 species where two people can't speak English, so the probability of this combination winning is 1/28.

Then, the probability that some members of the research group can speak English is P= 1- 1/28=27/28.

(3) The number of collocations in which only men can speak English is C (1.3) C (1.1) = 3, and the number of collocations in which only women can speak English is C (1.1) C (/kloc-0).

The probability that there are English speakers and members of the opposite sex in the research team is P=(3+ 1+3)/28= 1/4.