This is the problem in the second math draft 2- 1 ~ The straight line X2 +y2-6x+5=0 passing through the origin intersects at two points A and B, and the trajectory equation of the middle point m in th

This is the problem in the second math draft 2- 1 ~ The straight line X2 +y2-6x+5=0 passing through the origin intersects at two points A and B, and the trajectory equation of the middle point m in the chord AB is found. X2 +y2-6x+5=0, that is, (x-3) 2+y 2 = 4 is a circle.

The center of the circle C is (3,0) and M is the midpoint of the chord, so CM is perpendicular to AB.

The origin is O, so according to Pythagorean theorem, om 2+cm 2 = oc 2.

Let m be (x, y), x 2+y 2 = om 2 (x-3) 2+y 2 = cm 2c 2 = 9.

So x 2+y 2+(x-3) 2+y 2 = 9.

So the trajectory equation is 2x 2-6x+2y 2 = 0.

Simplify x 2+y 2-3x = o, and the range of values is appropriate.

I hope I can explain it clearly enough ~