1 should be divided into: No.98, No.2 and No.4, No.3 and No.5 1 respectively.
98 0 1 0 1
The reason is as follows: there is no possibility that the last pirate will be thrown, so let's start from the 5 th.
If you throw away the first four people, you can get 100 on the 5th.
If there are only No.4 and No.5 left, No.4 will give yourself 100, and No.5 will get 0, and your vote rate will reach 50%.
If there are only three people left, No.3 gives himself 99 yuan, No.5 gives himself 1 yuan, No.5 supports the method of No.3, plus one vote, and it is passed.
If the proposal is No.2, he will give himself 99 yuan to No.4, 1 yuan to support himself, taking into account the previous ideas of 3, 4 and 5.
1 thought of the method of 2, so the method of 1 should be 98 0 1 0 1.
No.3 and No.5 support 1, plus 1' s own 1 ticket, which can be passed.
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