You can think of it this way: the original question is equivalent to the full arrangement of eight positions, and the sixth is the probability of black ball.
So it is C( 1, 3) a (7,7)/a (8,8) = 3/8, and the same probability can be obtained every time.
The same type (that is, the same method of consideration) also has the problem of drawing lots, and the probability of drawing lots is the same whether drawing lots first or drawing lots later.