Then calculate:
1) A gets the red ball. But when he took the ball, there were three balls in his bag. The probability of getting the red ball is 1/3, right? It can be seen that he is not cheap
2) If Party B gets the red ball, it must get the white ball, and the probability of Party A getting the white ball is 2/3. Then the probability of Party B getting the red ball is 1/2. These two conditions must be met at the same time, so the probability of Party B getting the red ball is 2/3 * 1/2 = 1/3! There is no bargaining or loss.
3) No calculation is required. The remaining 1/3 is the probability that C gets the red ball.