How to arrange 2 1 players in the double-loss elimination system of table tennis

It should be that everyone is organized according to a certain competition order (the number is 1-2 1), and two adjacent people compete. The winner enters the next round, and the loser competes with the neighboring losers. Losing two games is eliminated, the runner-up is the one who loses only one game, and the winner is the champion. This is the concept of double elimination.

According to the above, I think 2 1 is an odd number, and it is necessary for one person to draw lots to decide the outcome of a game. If it is bye at 1 position, 2-3 4-5 6-7 8-910-12-. 14-1516-1718-19 20-21If this round wins 2, 5, 7, 8,/kloc. The negative team is 3-4 6-911-1214-19-21(whoever loses will be eliminated), and this round is 3, 6, 7. Negative continuation 3-6 1 1-17 191,elimination 3,11/9 This round continues to 65438. This time, 3, 1 1 wins, 1 and 19 are eliminated, followed by 3, 113 wins,1eliminated.

Next, the winners of the first round, No.2, No.5, No.7, No.8, 10, 13, 15, 16, 18, 20 and 3, will continue the competition. 2-5 7-8

10-1315-1618-20 continue to be eliminated by double defeat, and the winning team in the first round is the champion. The loser of the winning team who lost only one game in the first round competed with No.3 who lost only two games (two runners-up who lost only one game).

The above is my opinion for your reference ~