∫ The events involved in the experiment are five elements in 10, and * * * has C 105 results.
Player A's successful challenge is to choose 5 items from 8 items that can be crossed, and there is a C85 selection method.
∴ The probability of a player's successful challenge is: P 1=C58C5 10=29.
(2) According to the meaning of the question, the player challenged twice in a row.
I.e. independent repeated tests,
Then the probability that the player will succeed in two challenges is:
P2 = c 2 1p 1( 1-p 1)= 2×29×( 1-29)= 288 1