A math problem, assuming there are 49 numbers, what is the probability that a * * * extracts 7 numbers and the last number is exactly 49?

The first six cannot be 49.

Probability: 48/49 * 47/48 * 46/47 * 45/46 * 44/45 * 43/44 = 43/49.

The seventh is 49.

Probability: 1/43

So the probability that the last one is 49 is: 43/49* 1/43= 1/49.

In other words, the probability of opening any number at any position is the same.

This truth is like drawing lots.