A classic reasoning problem that many people have seen.

1. If No.5 is a person, all 100 gems are his;

2. If there are only two people (No.4 and No.5), according to the rules of the game, the proposal put forward by No.4 can only be passed if both people agree, and Pirate No.5 can get 100, so even if No.4 puts forward the distribution plan of 0. 100, Pirate No.5 will not agree to kill more people, so when there are only two people, Pirate No.4 will die;

3. If there are only three people on No.3, No.4 and No.5, the plan of No.3 must be100,0,0. At this time, the 4 th will definitely agree. Why? Because once the proposal of No.3 is rejected, No.4 will be dead, and life is the most important, so the plan is passed by two votes to one vote;

4. What if there are two, three, four or five? For No.2, his goal is that three people agree with his plan. At this time, his goal can be successfully achieved by giving No.4 and No.5 1 gem, so the plan of No.2 is: 98, 0, 65, 438+0, 65, 438+0;

5. Actually, the final decision on the allocation scheme is in the hands of 1. As long as he can get the support of the other two people, he will certainly get their approval. So 1 will definitely give him a gem in order to win over No.3, and if No.4 and No.5 give them a gem at this time, they will definitely get a gem in Plan No.2 anyway, so they won't kill others. How can they not veto it? Two gems for one of them, of course. At this time, if one of 1 and No.3 is added with No.4 and No.5 to get two gems, it will definitely make the plan pass smoothly, so the decision of 1 is 97,0, 1, 0,2 or 97,0, 1, 2.