Eight young volunteers participated in the service of the 9th National Universiade in Tianjin, of which four were assigned to the table tennis court and four to the swimming pool.

Let's assume that a volunteer is drawn from a table tennis court and a volunteer is drawn from a swimming pool. Their service numbers are X and Y, respectively, and (X, Y) indicates the drawing result.

Then all the possibilities are (1, 1), (1, 2), (1, 3), (1, 4) (2, 1), (2, 2.

Sixteen species (3 1), (3,2), (3,3), (3,4) (41), (4,2), (4,3), (4,4), * *.

(1) The service identification numbers of the two young volunteers transferred are adjacent integers. The results are as follows:

(1, 2), (2, 1), (2,3) (3,2), (3,4), (4,3) * *, so the probability is P = 6,16 = 3.8;

(3) The result that the sum of the service numbers of the transferred two young volunteers can be divisible by 3 is as follows:

(1, 2), (2, 1), (2,4) (3,3), (4,2) * *, so the probability P = 5,16;

Answer: (1) The probability that the service sign numbers of the two young volunteers being transferred are adjacent integers is 3.8;

(2) The probability that the sum of the service sign numbers of the two young volunteers being transferred can be divisible by 3 is 5 16.