(x-2b)(x-b)=0,
x=2b,x=b,
∫ Side lengths AC and AB are two roots of the equation x2-3bx+2b=0 about X, AC < BC,
∴b>0,AC=b,AB=2b,
From Pythagorean Theorem: BC=3b,
The circumference of ABC is b+2b+3b = (3+3) b.