In order to measure the sediment concentration of the Yellow River water, an extracurricular activity group obtained the Yellow River water of 10 dm3, and its mass was 10. 18kg. The known density of s

In order to measure the sediment concentration of the Yellow River water, an extracurricular activity group obtained the Yellow River water of 10 dm3, and its mass was 10. 18kg. The known density of sand is 2.5. Because the quality of the Yellow River water is equal to the sum of water and sand,

Therefore, from ρ=mV, we can get that the mass of the Yellow River water is 10dm3:

M=m water +m sand = ρ water v water+ρ sand v sand,

That is,10.18kg =1.0x103kg/m3× (10x10-3m3-v sand)+2.5x/kloc.

The solution is: 10dm3 of V sand in the Yellow River water =1.2xx10-4m3,

Then the volume of sand in 1m3 river water V= 100V sand =100×1.2×10-4m3 = 0.012m3,

1m3 river sand;

m =ρV = 2.5× 103kg/m3×0.0 12 m3 = 30k g，

That is, every cubic meter of Yellow River water contains 30 kilograms. Sediment.

So the answer is: 30.